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步数用尽时先收个尾,别把半截过程当答案交出去
走到步数上限一定意味着最后那步**要求了工具**(不要工具的话循环早 break 了), 也就是说模型从来没拿到过"说结论"的那一轮——它只是被掐断在半路。交出去的 是它上一句中间过程的话,末尾补一句"步数不够,请调大"。 实测这条线是绷紧的:库里 116 个 agent 节点,87% 在 10 步内收口,11 步只有 1 个,**正好 12 步的有 11 个**。1 跳到 11 是被截断的特征,不是自然分布。 所以补上那一轮:不给工具,让它基于已经查到的收口,并说清哪些没查到、 结论因此有什么局限。用 base_model 而不是绑过工具的 model——收尾轮必须在 结构上发不出 tool_call,靠提示词请它别调是约束不住的。 两种收场发不同的 code:收上来了是 step_limit_settled(DEGRADED), 收不上来仍是 step_limit(BROKEN)。不复用同一个 code:库里那 8 条老事件 的含义确实是硬截断,改语义等于把历史运行重新解释成另一回事。 顺带修掉一个一直在白烧钱的 bug:chat.ts:440 的注释说自动重试能"调大最大 步数",而 copilot.py 明确禁止模型写 max_steps。两边对不上,于是 step_limit 的重试是用同一个默认 12 再跑一遍,必然撞同一堵墙。现在那条禁令改成有条件 的——只有上一次死于步数不够时才准显式写大值。改完两条路各自成立:收尾 成功走 DEGRADED,闸门不开、不重试(对的,同配置再跑还是撞墙);收尾失败 仍是 BROKEN,而这次 Copilot 真能把步数调大。 硬顶 25 → 100,画布滑块跟着放开,**节点默认仍是 12**:要更多的人调得动, 不知情的人不会突然多花十倍。 新增 tests/test_agent_steps.py,顺带补回 agent 循环的集成测试(原来那个 文件在脱敏那轮被整个删掉了)。两条反向断言是重点:正常收口的 agent 一次 调用都不该多花,以及收尾轮发不出工具调用。两者都做过变异验证——把收尾 结果丢弃、把收尾轮换成绑工具的 model,各自都能让对应的断言变红。 273 passed(去掉一个会真连 api.openai.com 的既有慢测试是 238 passed / 9.4s)。
This commit is contained in:
@@ -112,8 +112,10 @@ NODE_REFERENCE = """\
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- output:出口,收集最终成果。config.fields = [{name, value}],value 里写模板引用
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- output:出口,收集最终成果。config.fields = [{name, value}],value 里写模板引用
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- llm:单次模型调用。config: {system, prompt, model, temperature, max_tokens, assign_to, output_schema}
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- llm:单次模型调用。config: {system, prompt, model, temperature, max_tokens, assign_to, output_schema}
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- agent:带工具循环的 agent。config: {system, prompt, tools:[工具名], approval, assign_to}
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- agent:带工具循环的 agent。config: {system, prompt, tools:[工具名], approval, assign_to}
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**不要写 max_steps**。平台默认值是按「一步只调一个工具」校准过的;写死一个
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**默认不要写 max_steps**。平台默认值是按「一步只调一个工具」校准过的;写死一个
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小数字(见过 8)会让它查完表结构就没额度回答了,用户拿到的是半截结论
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小数字(见过 8)会让它查完表结构就没额度回答了,用户拿到的是半截结论。
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唯一的例外:上一次就是因为**步数用尽**没跑完(会在改写理由里写明),
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这时要显式写一个更大的值(比如 24)——那是这种失败唯一的修法
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- supervisor:多 agent 协作。config: {goal, agents:[{name, description, system, tools, model}], max_rounds}
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- supervisor:多 agent 协作。config: {goal, agents:[{name, description, system, tools, model}], max_rounds}
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- tool:直接调一个工具。config: {tool: 工具名, args: {...}, assign_to}
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- tool:直接调一个工具。config: {tool: 工具名, args: {...}, assign_to}
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- code:沙箱里跑代码。config: {language: python|bash|node, code, timeout, network, assign_to}
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- code:沙箱里跑代码。config: {language: python|bash|node, code, timeout, network, assign_to}
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@@ -65,7 +65,10 @@ class Settings(BaseSettings):
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# --- 执行引擎护栏 ---
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# --- 执行引擎护栏 ---
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max_run_seconds: int = 600
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max_run_seconds: int = 600
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max_graph_steps: int = 200
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max_graph_steps: int = 200
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max_agent_steps: int = 25
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# 节点上配多少步都过不去这个硬顶。默认值仍是节点上的 12(nodeDefs.ts),
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# 这里只决定"想调大的人最多能调到哪"——实测 87% 的 agent 节点 ≤10 步就收口,
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# 绷紧的是那 10%,不该让所有人陪着多花钱
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max_agent_steps: int = 100
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#: 上传文件的大小上限(MB)。原来写死 10,而且是读完整个文件才检查——
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#: 上传文件的大小上限(MB)。原来写死 10,而且是读完整个文件才检查——
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#: 传一个 1GB 的文件,内存在报 413 之前就吃掉了
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#: 传一个 1GB 的文件,内存在报 413 之前就吃掉了
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max_upload_mb: int = 50
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max_upload_mb: int = 50
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@@ -353,6 +353,12 @@ async def run_agent(state: GraphState, ctx: NodeContext) -> dict[str, Any]:
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async def llm_step(step: int, payload: list[BaseMessage]) -> BaseMessage:
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async def llm_step(step: int, payload: list[BaseMessage]) -> BaseMessage:
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return await _invoke_streaming(model, payload, ctx, model_id)
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return await _invoke_streaming(model, payload, ctx, model_id)
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@task
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async def settle_step(payload: list[BaseMessage]) -> BaseMessage:
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# 用 base_model 而不是上面那个绑过工具的 model:收尾轮必须在**结构上**
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# 发不出工具调用,靠提示词说"别调工具"是约束不住的
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return await _invoke_streaming(base_model, payload, ctx, model_id)
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@task
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@task
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async def tool_step(step: int, name: str, args: dict[str, Any]) -> str:
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async def tool_step(step: int, name: str, args: dict[str, Any]) -> str:
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tool = tool_map[name]
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tool = tool_map[name]
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@@ -479,10 +485,44 @@ async def run_agent(state: GraphState, ctx: NodeContext) -> dict[str, Any]:
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{"tool": call.get("name", ""), "args": call.get("args", {}) or {}, "skipped": True}
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{"tool": call.get("name", ""), "args": call.get("args", {}) or {}, "skipped": True}
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)
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)
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else:
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else:
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# 步数用完了。成果只能取模型自己说过的话——messages[-1] 很可能是一条
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# 步数用完了。走到这儿一定意味着最后那步**要求了工具**(不要工具会 break),
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# ToolMessage:工具的原始返回,或者串行模式下那句"本轮只执行了第一个
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# 也就是说模型从来没拿到过"说结论"的那一轮——它只是被掐断在半路。
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# 工具"。后者真的漏到用户面前当过答案(run dd9927e6),一句内部管道
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#
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# 文案冒充结论,比明说"没跑完"糟糕得多。
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# 所以先补上那一轮:不给工具,让它基于已经查到的东西收口。这比把中间
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# 过程当答案交出去强得多,也比只留一句抱怨强——用户要的是"已知什么、
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# 还缺什么",不是"系统哪里不够用"。
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settled = ""
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messages.append(HumanMessage(content=(
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f"步数预算用完了({max_steps} 步),现在起不能再调用任何工具。"
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"基于已经查到的信息给出结论;明确说清哪些部分没有查到、"
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"结论因此有什么局限。不要编造没查到的数据。"
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)))
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try:
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response = await settle_step(messages)
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usage = _usage_of(response, model_id)
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for key in ("input_tokens", "output_tokens", "calls"):
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total_usage[key] += usage[key]
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total_usage["cost_usd"] = round(total_usage["cost_usd"] + usage["cost_usd"], 6)
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settled = message_text(response).strip()
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except Exception as e: # noqa: BLE001 - 收尾失败不能把已有成果一起赔进去
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ctx.emit(EventType.LOG, level="warn",
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message=f"收尾轮没跑成:{type(e).__name__}: {e}", code="settle_failed")
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if settled:
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final_text = settled
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hint = (
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f"agent 用满了 {max_steps} 步,这个结论是基于已经查到的部分给出的。"
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"要跑全请把节点上的「最大步数」调大;如果它大部分步数花在逐张表"
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"查结构上,也可以在提示词里点明该查哪几张表。"
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)
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# 和 step_limit 分开发:库里那些老事件的含义确实是"硬截断",
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# 复用同一个 code 会把历史运行重新解释成另一回事
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ctx.emit(EventType.LOG, level="warn", message=hint, code="step_limit_settled")
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else:
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# 收尾轮也没说出话。成果只能取模型自己说过的话——messages[-1] 很可能
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# 是一条 ToolMessage:工具的原始返回,或者串行模式下那句"本轮只执行了
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# 第一个工具"。后者真的漏到用户面前当过答案(run dd9927e6),一句内部
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# 管道文案冒充结论,比明说"没跑完"糟糕得多。
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final_text = next(
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final_text = next(
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(text for m in reversed(messages)
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(text for m in reversed(messages)
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if isinstance(m, AIMessage) and (text := message_text(m).strip())),
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if isinstance(m, AIMessage) and (text := message_text(m).strip())),
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@@ -58,6 +58,12 @@ WARN_CODES: dict[str, tuple[str, str]] = {
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"step_limit": ("step_limit", BROKEN),
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"step_limit": ("step_limit", BROKEN),
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"empty_completion": ("empty_completion", BROKEN),
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"empty_completion": ("empty_completion", BROKEN),
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# 能用但有缺口
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# 能用但有缺口
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# 步数用尽,但收尾轮让模型基于已查到的部分收了口:答案是完整的一段话,
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# 只是覆盖面不全——这是缺口不是断裂,所以不判 BROKEN。
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# 连带效果是不再触发自动重跑,那正是想要的:同样配置再跑一遍还撞同一堵墙
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"step_limit_settled": ("step_limit_settled", DEGRADED),
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# 收尾轮自己挂了。影响由同时发出的 step_limit(BROKEN) 承担,这条是说清原因
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"settle_failed": ("settle_failed", DEGRADED),
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"loop_limit": ("loop_limit", DEGRADED),
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"loop_limit": ("loop_limit", DEGRADED),
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"tool_args_fixed": ("tool_args_fixed", DEGRADED),
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"tool_args_fixed": ("tool_args_fixed", DEGRADED),
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"node_retry": ("node_retry", DEGRADED),
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"node_retry": ("node_retry", DEGRADED),
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@@ -0,0 +1,218 @@
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"""步数用尽时,agent 要收口,而不是把半截过程交出去。
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走到步数上限一定意味着最后那步**要求了工具**(不要工具的话循环早 break 了),
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也就是说模型从来没拿到过"说结论"的那一轮——它只是被掐断在半路。交出去的
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是它上一句中间过程的话,末尾补一句"步数不够"。
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所以补上那一轮:不给工具,让它基于已经查到的收口。这里守三件事——收尾轮
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真的发生了、它**发不出**工具调用、以及它没有变成每次都多烧的一次调用。
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顺带补回 agent 循环的集成测试:原来那个文件在脱敏那轮被整个删掉了。
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"""
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from __future__ import annotations
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import asyncio
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import pytest
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from langchain_core.messages import AIMessage
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from sqlalchemy import select
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from app.db.base import SessionLocal
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from app.db.models import Run, RunEvent
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from app.engine.runner import run_manager
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#: 收尾轮该说的话。挑一句和"中间过程"截然不同的,好分辨答案到底取自哪一轮
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SETTLED = "已经查到的部分:门店 8 家。其余未查到,这个数是下限。"
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MIDWAY = "中间过程:还得再查一张表。"
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MAX_STEPS = 3
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@pytest.fixture
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async def runner():
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await run_manager.setup()
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yield run_manager
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await run_manager.shutdown()
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def _graph(*, max_steps: int = MAX_STEPS) -> dict:
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return {
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"nodes": [
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{"id": "in", "type": "input", "data": {"config": {}}},
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{"id": "work", "type": "agent", "data": {"config": {
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"prompt": "{{ input.question }}",
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"tools": ["calculator"],
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"max_steps": max_steps,
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"approval": "never",
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}}},
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{"id": "out", "type": "output", "data": {"config": {}}},
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],
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"edges": [{"source": "in", "target": "work"}, {"source": "work", "target": "out"}],
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}
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def never_concludes(monkeypatch, *, settle_raises: bool = False) -> None:
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"""绑了工具就永远再要一次工具;没绑工具才说话。
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`self.tools` 是 bind_tools 之后才有的。收尾轮走的是**没绑过工具**的
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base_model,所以它必然落到下面那个分支——这正是"收尾轮发不出工具调用"
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那条断言的着力点:真要是绑着工具过来的,拿到的就会是 MIDWAY。
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"""
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from app.providers import mock_model
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def _decide(self, messages):
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if self.tools:
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return AIMessage(
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content=MIDWAY,
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tool_calls=[{"name": self.tools[0]["name"],
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"args": {"expression": "1+1"},
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"id": f"call_{len(messages)}"}],
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)
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if settle_raises:
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raise RuntimeError("收尾轮炸了")
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return AIMessage(content=SETTLED)
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monkeypatch.setattr(mock_model.MockChatModel, "_decide", _decide)
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async def _run(graph: dict, question: str = "有几家门店"):
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run = await run_manager.start(graph=graph, input_payload={"question": question})
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for _ in range(200):
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await asyncio.sleep(0.05)
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async with SessionLocal() as session:
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row = (await session.execute(select(Run).where(Run.id == run.id))).scalar_one()
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if row.status in ("succeeded", "failed", "cancelled"):
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break
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else:
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pytest.fail("运行没有在 10 秒内结束")
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async with SessionLocal() as session:
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events = list((await session.execute(
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select(RunEvent).where(RunEvent.run_id == run.id).order_by(RunEvent.seq)
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)).scalars())
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return events, row
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def codes(events) -> list[str]:
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return [e.data.get("code") for e in events
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if e.type == "log" and (e.data or {}).get("level") == "warn"]
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def answer_of(row) -> str:
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from app.engine import review as rv
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return rv.answer_text(row.output)
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# --------------------------------------------------------------------------
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@pytest.mark.asyncio
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async def test_step_limit_ends_with_a_conclusion_not_a_stump(runner, monkeypatch) -> None:
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"""这块改动的全部意义:交出去的是结论,不是中间过程加一句抱怨。"""
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never_concludes(monkeypatch)
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events, row = await _run(_graph())
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assert row.status == "succeeded", row.error
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text = answer_of(row)
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assert SETTLED in text, text
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assert MIDWAY not in text, f"上一句中间过程冒充了答案:{text}"
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assert "step_limit_settled" in codes(events), codes(events)
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|
|
||||||
|
|
||||||
|
@pytest.mark.asyncio
|
||||||
|
async def test_the_settle_round_has_no_tools_bound(runner, monkeypatch) -> None:
|
||||||
|
"""收尾轮必须在**结构上**发不出工具调用,而不是靠提示词请它别调。
|
||||||
|
|
||||||
|
mock 的判据就是"有没有绑工具":真要是把绑过工具的 model 传进了收尾轮,
|
||||||
|
它会照常再要一次工具,答案里出现的就是 MIDWAY。
|
||||||
|
"""
|
||||||
|
never_concludes(monkeypatch)
|
||||||
|
events, row = await _run(_graph())
|
||||||
|
|
||||||
|
assert SETTLED in answer_of(row)
|
||||||
|
# 工具调用次数正好等于步数——收尾轮一次都没多调
|
||||||
|
assert len([e for e in events if e.type == "tool.start"]) == MAX_STEPS
|
||||||
|
|
||||||
|
|
||||||
|
@pytest.mark.asyncio
|
||||||
|
async def test_the_settle_round_costs_exactly_one_extra_call(runner, monkeypatch) -> None:
|
||||||
|
"""多花的必须是可数的一次,不是一个说不清的尾巴。"""
|
||||||
|
never_concludes(monkeypatch)
|
||||||
|
events, _ = await _run(_graph())
|
||||||
|
assert len([e for e in events if e.type == "llm.start"]) == MAX_STEPS + 1
|
||||||
|
|
||||||
|
|
||||||
|
@pytest.mark.asyncio
|
||||||
|
async def test_a_normal_agent_does_not_pay_for_a_settle_round(runner, monkeypatch) -> None:
|
||||||
|
"""反向断言:正常收口的 agent 一分钱都不该多花。
|
||||||
|
|
||||||
|
没有这条,"每次都多跑一轮"这种退化会悄无声息地通过全部其他测试。
|
||||||
|
"""
|
||||||
|
from app.providers import mock_model
|
||||||
|
|
||||||
|
monkeypatch.setattr(mock_model.MockChatModel, "_decide",
|
||||||
|
lambda self, messages: AIMessage(content="直接就有结论了。"))
|
||||||
|
events, row = await _run(_graph())
|
||||||
|
|
||||||
|
assert "直接就有结论了。" in answer_of(row)
|
||||||
|
assert len([e for e in events if e.type == "llm.start"]) == 1
|
||||||
|
assert not [c for c in codes(events) if c and c.startswith("step_limit")]
|
||||||
|
|
||||||
|
|
||||||
|
@pytest.mark.asyncio
|
||||||
|
async def test_a_failed_settle_round_falls_back_and_keeps_what_was_found(
|
||||||
|
runner, monkeypatch
|
||||||
|
) -> None:
|
||||||
|
"""收尾轮自己挂了,不能把已经查到的一起赔进去。"""
|
||||||
|
never_concludes(monkeypatch, settle_raises=True)
|
||||||
|
events, row = await _run(_graph())
|
||||||
|
assert row.status == "succeeded", row.error
|
||||||
|
|
||||||
|
text = answer_of(row)
|
||||||
|
assert "settle_failed" in codes(events), codes(events)
|
||||||
|
# 退回原来的行为:老的 step_limit(BROKEN),而不是 settled 那个
|
||||||
|
assert "step_limit" in codes(events)
|
||||||
|
assert "step_limit_settled" not in codes(events)
|
||||||
|
# 已有成果还在,末尾挂着说明
|
||||||
|
assert MIDWAY in text and "用满了" in text, text
|
||||||
|
|
||||||
|
|
||||||
|
def test_max_steps_is_clamped_by_the_hard_cap() -> None:
|
||||||
|
"""节点上写多大都过不去硬顶——否则一张图就能把预算烧穿。"""
|
||||||
|
from app.core.config import settings
|
||||||
|
|
||||||
|
assert min(200, settings.max_agent_steps) == settings.max_agent_steps
|
||||||
|
assert settings.max_agent_steps >= 25, "抬高上限不该反而把原来能配的值挡回去"
|
||||||
|
|
||||||
|
|
||||||
|
# --------------------------------------------------------------------------
|
||||||
|
# 复核层怎么看这两种收场
|
||||||
|
# --------------------------------------------------------------------------
|
||||||
|
|
||||||
|
|
||||||
|
def _warn(message: str, code: str) -> dict:
|
||||||
|
return {"type": "log", "node_id": "work",
|
||||||
|
"data": {"level": "warn", "message": message, "code": code}}
|
||||||
|
|
||||||
|
|
||||||
|
OK_OUTPUT = {"text": SETTLED}
|
||||||
|
|
||||||
|
|
||||||
|
def test_a_settled_run_is_a_gap_not_a_break() -> None:
|
||||||
|
"""收口过的答案是完整一段话,只是覆盖面不全——那是缺口不是断裂。"""
|
||||||
|
from app.engine import review as rv
|
||||||
|
|
||||||
|
signals = rv.scan([_warn("用满了 3 步,基于已查到的部分给出", "step_limit_settled")],
|
||||||
|
OK_OUTPUT)
|
||||||
|
assert [s.severity for s in signals] == [rv.DEGRADED]
|
||||||
|
# 连带效果正是想要的:不再触发自动重跑
|
||||||
|
assert not rv.should_retry(signals)
|
||||||
|
|
||||||
|
|
||||||
|
def test_a_hard_truncation_is_still_broken_and_still_retries() -> None:
|
||||||
|
"""收尾轮没能收上来,判定一点没变——这条是防止改动把老路一起改坏。"""
|
||||||
|
from app.engine import review as rv
|
||||||
|
|
||||||
|
signals = rv.scan([_warn("用满了 3 步还没给出结论", "step_limit")], OK_OUTPUT)
|
||||||
|
assert rv.worst(signals) == rv.BROKEN
|
||||||
|
assert rv.should_retry(signals)
|
||||||
@@ -133,7 +133,7 @@ export const NODE_DEFS: Record<NodeType, NodeDef> = {
|
|||||||
{ key: 'prompt', label: '任务', type: 'prompt' },
|
{ key: 'prompt', label: '任务', type: 'prompt' },
|
||||||
{ key: 'tools', label: '可用工具', type: 'tools' },
|
{ key: 'tools', label: '可用工具', type: 'tools' },
|
||||||
{ key: 'skills', label: '挂载 Skill', type: 'skills' },
|
{ key: 'skills', label: '挂载 Skill', type: 'skills' },
|
||||||
{ key: 'max_steps', label: '最大步数', type: 'number', min: 1, max: 25 },
|
{ key: 'max_steps', label: '最大步数', type: 'number', min: 1, max: 100 },
|
||||||
{
|
{
|
||||||
key: 'approval', label: '工具审批', type: 'select',
|
key: 'approval', label: '工具审批', type: 'select',
|
||||||
options: [
|
options: [
|
||||||
|
|||||||
Reference in New Issue
Block a user