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ThearchyHelios 0d9f1d9339 用户看得到的列表补决胜键(复核 R-a9):按名称、时间等可能并列的排序后面补上同一个模型的 id,并列时两种库排出来一样
- 实测 /api/evals/calibers、/api/schedules/trigger-options 按 Workflow.name 排序遇同名并列时 SQLite、PostgreSQL 顺序不同。用 AST 逐个过了一遍 order_by:最后一个排序键是 created_at / updated_at / last_active_at / at / name / 各种 *_at 之类、不唯一的列,又不带 DISTINCT、GROUP BY 的,补「, 模型.id」(降序补 id.desc()),共 104 处,分布在 api、apps、auth、blueprints、chat、data、engine、eval、ledger、look、memory、process、providers、scheduler(runs.py 里的三处在上一个提交里)
- 按唯一列(seq、version、唯一的 name)排的不动;按聚合、coalesce 之类表达式排的说明见 db/postgres
2026-10-19 12:07:06 +08:00

136 lines
5.3 KiB
Python

from __future__ import annotations
from collections import defaultdict
from typing import Any
from fastapi import APIRouter, Depends, HTTPException, Query
from sqlalchemy import select
from sqlalchemy.ext.asyncio import AsyncSession
from app.db.base import get_session
from app.db.models import Run, RunEvent, Workflow
from app.engine.schema import GraphSpec, NodeType
router = APIRouter(prefix="/api/governance", tags=["governance"])
@router.get("/tool-usage")
async def tool_usage(
workflow_id: str,
limit_runs: int = Query(default=100, le=500),
session: AsyncSession = Depends(get_session),
) -> dict[str, Any]:
"""工具白名单衰减报表。
关节层最可能的退化方式不是模板太死,而是白名单为了长尾一个个放宽,
半年后等于没有白名单。这份报表把"授了权但从来没用过"的工具摆到台面上,
放宽才能被定期回收。
"""
workflow = await session.get(Workflow, workflow_id)
if not workflow:
raise HTTPException(404, "工作流不存在,可能已被删除")
spec = GraphSpec.model_validate(workflow.graph)
# 各节点声明的白名单
granted: dict[str, list[str]] = {}
for node in spec.nodes:
if node.type == NodeType.AGENT:
granted[node.id] = list(node.config.get("tools") or [])
elif node.type == NodeType.TOOL and node.config.get("tool"):
granted[node.id] = [node.config["tool"]]
elif node.type == NodeType.SUPERVISOR:
merged: list[str] = []
for agent in node.config.get("agents") or []:
merged.extend(agent.get("tools") or [])
granted[node.id] = sorted(set(merged))
from app.engine.origin import counted_runs
# 只算计入统计的运行(engine/origin.counted_runs):评测、口径对账、召回替人跑的运行用到了哪些工具不说明白名单该不该收
run_ids = [
rid
for (rid,) in await session.execute(
select(Run.id)
.where(Run.workflow_id == workflow_id, counted_runs())
.order_by(Run.created_at.desc(), Run.id.desc())
.limit(limit_runs)
)
]
usage: dict[str, dict[str, int]] = defaultdict(lambda: defaultdict(int))
if run_ids:
rows = await session.execute(
select(RunEvent.node_id, RunEvent.data).where(
RunEvent.run_id.in_(run_ids), RunEvent.type == "tool.start"
)
)
for node_id, data in rows:
tool = (data or {}).get("tool")
if node_id and tool:
# supervisor 内部子 agent 的 node_id 形如 "team:researcher"
usage[node_id.split(":")[0]][tool] += 1
report = []
for node_id, tools in granted.items():
used = usage.get(node_id, {})
report.append(
{
"node_id": node_id,
"granted": tools,
"used": dict(used),
"unused": [t for t in tools if not used.get(t)],
"ungrated_but_used": [t for t in used if t not in tools],
}
)
return {
"workflow_id": workflow_id,
"runs_considered": len(run_ids),
"nodes": report,
"hint": "授权后多次运行都未使用的工具说明授权范围偏宽,建议从节点中移除",
}
@router.get("/exploratory-clusters")
async def exploratory_clusters(
limit: int = Query(default=200, le=500),
threshold: float = Query(default=0.62, ge=0.3, le=0.95),
session: AsyncSession = Depends(get_session),
) -> dict[str, Any]:
"""探索性问题聚类:同一个问题被反复问,就该长成模板里的固定一节。
这就是模板生长的触发器。取问题、聚类全站只有一份(app/chat/questions.py):只取问题原文(不含 history),问数据一轮
一条(自动重来不多算),评测这类系统派生的运行、别人的个人应用刷新和个人蓝图试运行都不进。出现 ≥3 次的簇标记为晋升
候选。embedder 是聚类用的向量模型:本地哈希的语义能力弱,结果只是下限。
"""
from app.api.deps import current_principal
from app.chat.questions import cluster_questions, embedder, recent_questions
questions = await recent_questions(session, current_principal(), limit=limit)
if not questions:
return {"clusters": [], "considered": 0, "embedder": embedder()}
clusters = await cluster_questions(questions, threshold=threshold)
def _at(value: Any) -> str | None:
return value.isoformat() if value else None
out = [
{
"count": c.count,
"representative": c.members[0].text[:200],
"workflow": c.members[0].workflow,
"run_ids": [m.run_id for m in c.members if m.run_id][:20],
"turn_ids": [m.turn_id for m in c.members if m.turn_id][:20],
"first_at": _at(c.members[-1].at),
"last_at": _at(c.members[0].at),
"promote_candidate": c.count >= 3,
}
for c in clusters
if c.count >= 2
]
out.sort(key=lambda c: c["count"], reverse=True)
return {
"clusters": out,
"considered": len(questions),
"embedder": embedder(),
"hint": "被标记为可固化的问题反复出现,建议用「提取模板」把它固定为工作流中的一步",
}